document.write( "Question 232142: melissa can clean the house in 4hours, whereas her husband, zack, can do the same job in 5 hours. They have agreed to clean together so that they can finish in the to watch a movie on TV that starts in 2 hours. How long will it take them to clean the house together? Can they finish before the movie starts? \n" ); document.write( "
Algebra.Com's Answer #171649 by ankor@dixie-net.com(22740)\"\" \"About 
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melissa can clean the house in 4hours, whereas her husband, zack, can do the same job in 5 hours.
\n" ); document.write( " They have agreed to clean together so that they can finish in the to watch a movie on TV that starts in 2 hours.
\n" ); document.write( "How long will it take them to clean the house together? Can they finish before the movie starts?
\n" ); document.write( ":
\n" ); document.write( "Let t = time required working together
\n" ); document.write( ":
\n" ); document.write( "Let the completed job (a clean house) = 1
\n" ); document.write( ":
\n" ); document.write( "\"t%2F4\" + \"t%2F5\" = 1
\n" ); document.write( "multiply by 20
\n" ); document.write( "5t + 4t = 20
\n" ); document.write( "9t = 20
\n" ); document.write( "t = \"20%2F9\"
\n" ); document.write( "t = 2.22 hrs, so no they can't, they will be about 13 min late
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