document.write( "Question 232142: melissa can clean the house in 4hours, whereas her husband, zack, can do the same job in 5 hours. They have agreed to clean together so that they can finish in the to watch a movie on TV that starts in 2 hours. How long will it take them to clean the house together? Can they finish before the movie starts? \n" ); document.write( "
Algebra.Com's Answer #171649 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! melissa can clean the house in 4hours, whereas her husband, zack, can do the same job in 5 hours. \n" ); document.write( " They have agreed to clean together so that they can finish in the to watch a movie on TV that starts in 2 hours. \n" ); document.write( "How long will it take them to clean the house together? Can they finish before the movie starts? \n" ); document.write( ": \n" ); document.write( "Let t = time required working together \n" ); document.write( ": \n" ); document.write( "Let the completed job (a clean house) = 1 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( "multiply by 20 \n" ); document.write( "5t + 4t = 20 \n" ); document.write( "9t = 20 \n" ); document.write( "t = \n" ); document.write( "t = 2.22 hrs, so no they can't, they will be about 13 min late \n" ); document.write( " |