document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=232072>Question 232072</A>: <I><SPAN STYLE=\"word-break: break-all;\"> what is the setup for this distance problem:\r<BR>\n" );
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document.write( "At 10 am a plane leaves Boston MA, for Seattle, WA, a distance of 3000 miles. One hour later a plane leaves Seattle for Boston. Both planes are traveling at a speed of 500 mph. How many hours after the plane leaves Seattle will the planes pass each other? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #171601 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=171601\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> At 10 am a plane leaves Boston MA, for Seattle, WA, a distance of 3000 miles. One hour later a plane leaves Seattle for Boston. Both planes are traveling at a speed of 500 mph. How many hours after the plane leaves Seattle will the planes pass each other?<BR>\n" );
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document.write( "When the 2nd plane takes off, the 1st is 2500 miles away.<BR>\n" );
document.write( "Their combined speed is 1000 mph, so they'll cover the distance in 2.5 hours (2500/1000).<BR>\n" );
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document.write( "--> 2.5 hours after the 2nd plane leaves Seattle. </SPAN>\n" );
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