document.write( "Question 232027: the second of three numbers is 6 more than the first. the third number is twice the first. the sum of the three numbers is 26. find the three numbers.
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Algebra.Com's Answer #171575 by Robb(9)\"\" \"About 
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Ok, so let x equal the first number we don't know.\r
\n" ); document.write( "\n" ); document.write( "Then, since the 2nd number is 6 more than (+) the first number (x), let the second number equal x+6.\r
\n" ); document.write( "\n" ); document.write( "Then, since the 3rd number is \"twice\" the first, multiply x by 2 to let the third number equal 2x.\r
\n" ); document.write( "\n" ); document.write( "Now, the sum of all three numbers is 26.\r
\n" ); document.write( "\n" ); document.write( "So we simply add all our numbers and set them equal to 26:\r
\n" ); document.write( "\n" ); document.write( "x+(x+6)+2x=26\r
\n" ); document.write( "\n" ); document.write( "Now we combine terms to get:\r
\n" ); document.write( "\n" ); document.write( "4x+6=26\r
\n" ); document.write( "\n" ); document.write( "To get x alone, you subtract 6 from both sides:\r
\n" ); document.write( "\n" ); document.write( "4x=20\r
\n" ); document.write( "\n" ); document.write( "Then divide both sides by 4!\r
\n" ); document.write( "\n" ); document.write( "x=5\r
\n" ); document.write( "\n" ); document.write( "So since x (your first number) equals 5, the second number (x+6) is going to be 11... Then your third number (2x) has to equal 10...\r
\n" ); document.write( "\n" ); document.write( "Check these by adding:\r
\n" ); document.write( "\n" ); document.write( "5+11+10=26\r
\n" ); document.write( "\n" ); document.write( "These problems may be hard at first, but once you get the hang of them, they're a breeze. Start by getting down what symbols (+,-,*) they ask for in word problems by using words like (more, less than, sum, difference, twice the first, three times, etc..) Any more problems, just post them. There's a lot of smart people on here.\r
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