document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=231986>Question 231986</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am stumped on this question I need to evaluate this\r<BR>\n" );
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document.write( "Evaluate P(-1/2) if P(x)=2x^4+x^3+12 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #171538 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=171538\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Evaluate P(-1/2) if P(x)=2x^4+x^3+12<BR>\n" );
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document.write( "Sub -1/2 for x<BR>\n" );
document.write( "P(-1/2) = 2(-1/2)^4 + (-1/2)^3 + 12<BR>\n" );
document.write( "= 2*(1/16) + (-1/8) + 12<BR>\n" );
document.write( "= 1/8 - 1/8 + 12<BR>\n" );
document.write( "= 12\r<BR>\n" );
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document.write( " </SPAN>\n" );
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