document.write( "Question 231918: Robert invests $8000 in a bank. Part is invested at 7% simple interest and part at 9% simple interest. In one year Robert earns $660 in interest. How much did he invest at each amount? \n" ); document.write( "
Algebra.Com's Answer #171521 by checkley77(12844)\"\" \"About 
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.09X+.07(8,000-X)=660
\n" ); document.write( ".09X+560-.07X=660
\n" ); document.write( ".02X=660-560
\n" ); document.write( ".02X=100
\n" ); document.write( "X=100/.02
\n" ); document.write( "X=5,000 AMOUNT INVESTED @ 9%.
\n" ); document.write( "8,000-5,000=3,000 AMOUNT INVESTED @ 7%.
\n" ); document.write( "PROOF:
\n" ); document.write( ".09*5,000+.07*3,000=660
\n" ); document.write( "450+210=660
\n" ); document.write( "660=660
\n" ); document.write( "
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