document.write( "Question 231932: I have so many problems with word problems and I really don't know how to set up the problem please help.\r
\n" ); document.write( "\n" ); document.write( "Jose invested a certain amonunt of money at 8% interest and $300 more than that amount at 11%. His total yearly interest was $69.10. How much did he invest at the 8% rate?
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Algebra.Com's Answer #171517 by checkley77(12844)\"\" \"About 
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.08X+.11(300+X)=69.10
\n" ); document.write( ".08X+33+.11X=69.10
\n" ); document.write( ".19X=69.10-33
\n" ); document.write( ".19X=36.10
\n" ); document.write( "X=36.10/.19
\n" ); document.write( "X=$190 ANS. FOR THE INVESTMENT @ 8%.
\n" ); document.write( "300+190=490 ANS. FOR THE INVESTMENT @ 11%.
\n" ); document.write( "PROOF:
\n" ); document.write( ".08*190+.11*490=69.10
\n" ); document.write( "15.2+53.9=69.10
\n" ); document.write( "69.1=69.1
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