document.write( "Question 231929: A solution containing 30% alcohol is to be mixed with a solution containing 50%
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document.write( "alcohol to make 200 L of a solution containing 42% alcohol. How much of the 50%
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document.write( "solution should be used? \n" );
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Algebra.Com's Answer #171505 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A solution containing 30% alcohol is to be mixed with a solution containing 50% \n" ); document.write( "alcohol to make 200 L of a solution containing 42% alcohol. How much of the 50% \n" ); document.write( "solution should be used? \n" ); document.write( "---------------------- \n" ); document.write( "Equation: \n" ); document.write( "alcohol + alcohol = alcohol \n" ); document.write( "0.30x + 0.50(200-x) = 0.42*200 \n" ); document.write( "Multiply thru by 100 to get: \n" ); document.write( "30x + 50*200 - 50x = 42*200 \n" ); document.write( "-20x = -8*200 \n" ); document.write( "x = 80 liters (amount of 30% solution needed in the mixture) \n" ); document.write( "================================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |