document.write( "Question 231631: use the given conditions to write an equation for the line in point-slop form, slope intercept form, and standard form.\r
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document.write( "Passing though(1,-2)and parallel to the line whose equation is 2x-4y=9 \n" );
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Algebra.Com's Answer #171472 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Use the given conditions to write an equation for the line in point-slope form, \n" ); document.write( " slope intercept form, and standard form. \n" ); document.write( "Passing though(1,-2)and parallel to the line whose equation is 2x-4y=9 \n" ); document.write( ": \n" ); document.write( "Find the slope of the given equation by finding the slope/intercept form \n" ); document.write( "2x - 4y = 9 \n" ); document.write( "-4y = -2x + 9 \n" ); document.write( "We need y to be positive, multiply equation by -1 \n" ); document.write( "4y = 2x - 9 \n" ); document.write( "Divide equation by 4 \n" ); document.write( "y = \n" ); document.write( "y = .5x - 2.25 \n" ); document.write( ": \n" ); document.write( "slope (m) = .5 \n" ); document.write( ": \n" ); document.write( "Parallel lines have the same slope; use the point/slope form to find the equation: y - y1 = m(x-x1) \n" ); document.write( "In this equation: m=.5; x1=1; y1=-2 \n" ); document.write( "y - (-2) = .5(x - 1); the point slope form \n" ); document.write( "y + 2 = .5x - .5 \n" ); document.write( "y = .5x - .5 - 2 \n" ); document.write( "y = .5x - 2.5; the slope intercept form \n" ); document.write( ": \n" ); document.write( "Find the standard form \n" ); document.write( "y = .5x - 2.5 \n" ); document.write( "-.5x + y = -2.5 \n" ); document.write( "Multiply eq by -2 \n" ); document.write( "x - 2y = 5; the standard form of the line parallel to 2x - 4y = 9 \n" ); document.write( " |