document.write( "Question 231631: use the given conditions to write an equation for the line in point-slop form, slope intercept form, and standard form.\r
\n" ); document.write( "\n" ); document.write( "Passing though(1,-2)and parallel to the line whose equation is 2x-4y=9
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Algebra.Com's Answer #171472 by ankor@dixie-net.com(22740)\"\" \"About 
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Use the given conditions to write an equation for the line in point-slope form,
\n" ); document.write( " slope intercept form, and standard form.
\n" ); document.write( "Passing though(1,-2)and parallel to the line whose equation is 2x-4y=9
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\n" ); document.write( "Find the slope of the given equation by finding the slope/intercept form
\n" ); document.write( "2x - 4y = 9
\n" ); document.write( "-4y = -2x + 9
\n" ); document.write( "We need y to be positive, multiply equation by -1
\n" ); document.write( "4y = 2x - 9
\n" ); document.write( "Divide equation by 4
\n" ); document.write( "y = \"2%2F4\"x - \"9%2F4\"
\n" ); document.write( "y = .5x - 2.25
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\n" ); document.write( "slope (m) = .5
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\n" ); document.write( "Parallel lines have the same slope; use the point/slope form to find the equation: y - y1 = m(x-x1)
\n" ); document.write( "In this equation: m=.5; x1=1; y1=-2
\n" ); document.write( "y - (-2) = .5(x - 1); the point slope form
\n" ); document.write( "y + 2 = .5x - .5
\n" ); document.write( "y = .5x - .5 - 2
\n" ); document.write( "y = .5x - 2.5; the slope intercept form
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\n" ); document.write( "Find the standard form
\n" ); document.write( "y = .5x - 2.5
\n" ); document.write( "-.5x + y = -2.5
\n" ); document.write( "Multiply eq by -2
\n" ); document.write( "x - 2y = 5; the standard form of the line parallel to 2x - 4y = 9
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