document.write( "Question 30524: I think I know the answer but can't get the formula right. HELP!!!
\n" ); document.write( "From a group of boys and girls, fifteen girls leave. Twice as many boys as girls are left. Then forty-five boys leave. Five times as many girls as boys remain. How many boys and girls were in the initial group?
\n" ); document.write( "

Algebra.Com's Answer #17146 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
b= initial number of boys
\n" ); document.write( "g = initial number of girls
\n" ); document.write( "when 15 girls leave, there are twice as many boys as girls
\n" ); document.write( "b = 2(g-15)
\n" ); document.write( "45 boys leave, 5 times as many girls remain
\n" ); document.write( "5(b-45) = g - 15
\n" ); document.write( "5b -225 = g - 15
\n" ); document.write( "from above
\n" ); document.write( "b/2 = g - 15
\n" ); document.write( "substitute
\n" ); document.write( "5b - 225 = b/2
\n" ); document.write( "10b -450 = b
\n" ); document.write( "9b = 450
\n" ); document.write( "b = 50
\n" ); document.write( "50/2 = g - 15
\n" ); document.write( "g = 25 + 15
\n" ); document.write( "g = 40
\n" ); document.write( "check
\n" ); document.write( "initially
\n" ); document.write( "b = 50
\n" ); document.write( "g = 40
\n" ); document.write( "15 girls leave
\n" ); document.write( "b = 50
\n" ); document.write( "g = 25
\n" ); document.write( "there are twice as many boys as girls
\n" ); document.write( "45 boys leave
\n" ); document.write( "b = 5
\n" ); document.write( "g = 25
\n" ); document.write( "five times as many girls remain
\n" ); document.write( "checks OK
\n" ); document.write( "
\n" );