document.write( "Question 30524: I think I know the answer but can't get the formula right. HELP!!!
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document.write( "From a group of boys and girls, fifteen girls leave. Twice as many boys as girls are left. Then forty-five boys leave. Five times as many girls as boys remain. How many boys and girls were in the initial group? \n" );
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Algebra.Com's Answer #17146 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! b= initial number of boys \n" ); document.write( "g = initial number of girls \n" ); document.write( "when 15 girls leave, there are twice as many boys as girls \n" ); document.write( "b = 2(g-15) \n" ); document.write( "45 boys leave, 5 times as many girls remain \n" ); document.write( "5(b-45) = g - 15 \n" ); document.write( "5b -225 = g - 15 \n" ); document.write( "from above \n" ); document.write( "b/2 = g - 15 \n" ); document.write( "substitute \n" ); document.write( "5b - 225 = b/2 \n" ); document.write( "10b -450 = b \n" ); document.write( "9b = 450 \n" ); document.write( "b = 50 \n" ); document.write( "50/2 = g - 15 \n" ); document.write( "g = 25 + 15 \n" ); document.write( "g = 40 \n" ); document.write( "check \n" ); document.write( "initially \n" ); document.write( "b = 50 \n" ); document.write( "g = 40 \n" ); document.write( "15 girls leave \n" ); document.write( "b = 50 \n" ); document.write( "g = 25 \n" ); document.write( "there are twice as many boys as girls \n" ); document.write( "45 boys leave \n" ); document.write( "b = 5 \n" ); document.write( "g = 25 \n" ); document.write( "five times as many girls remain \n" ); document.write( "checks OK \n" ); document.write( " |