document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=231691>Question 231691</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A customer desires to mix her own concrete.  The clerk knows that the ratio of cement to sand to gravel is 1:3:4.  If the customer needs 1,000 pounds of dry mix, how many pounds of each ingredient should she use?\r<BR>\n" );
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document.write( "Please use cross products </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #171454 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=171454\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The direct way to solve this problem is to add the three ratios:<BR>\n" );
document.write( "1+3+4=8 <BR>\n" );
document.write( "Now find how many sets of 8 there are in the total of 1,000.<BR>\n" );
document.write( "1,000/8=125 for each 1 of the elements in the ratio.<BR>\n" );
document.write( "1*125=125 pds. of cement.<BR>\n" );
document.write( "3*125=375 pds. of sand.<BR>\n" );
document.write( "4*125=500 pds. of gravel.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "125+375+500=1,000<BR>\n" );
document.write( "1,000=1,000<BR>\n" );
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