document.write( "Question 231683: For mutually exclusive events X1, X2, and X3, let P(X1) = .22, P(X2) = .35 and P(X3) = .43. Also, P(Y | Y1) = .40 P(Y|X2) = .30 and P(Y|X3) = .60. Find P(X3|Y)\r
\n" ); document.write( "\n" ); document.write( "A) . 20 B) . 57 C) . 38 D) . 23 \r
\n" ); document.write( "\n" ); document.write( "This theorem is so complicated for me that I dont know where to begin.
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Algebra.Com's Answer #171421 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
For mutually exclusive events X1, X2, and X3,
\n" ); document.write( "let P(X1) = .22, P(X2) = .35 and P(X3) = .43.
\n" ); document.write( "Also, P(Y | X1) = .40 P(Y|X2) = .30 and P(Y|X3) = .60.
\n" ); document.write( "Find P(X3|Y)
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\n" ); document.write( "P(X3 | Y) = P(X3 and Y)/P(Y)
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\n" ); document.write( "You are told P(Y | X3) = 0.6
\n" ); document.write( "So P(Y and X3)/P(X3) = 0.6
\n" ); document.write( "and P(Y and X3)/0.43 = 0.6
\n" ); document.write( "So, P(Y and X3) = 0.43*0.6 = 0.258
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\n" ); document.write( "Using that result you have:
\n" ); document.write( "P(X3 | Y) = 0.258/P(Y)
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\n" ); document.write( "But P(Y) = P(Y|X1) + P(Y|X2) + P(Y|X3) = 0.4 + 0.3 + 0.6 = 1.3
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\n" ); document.write( "Final Answer: P(X3 |Y) = 0.258/1.3 = 0.198
\n" ); document.write( "Round you be 0.20
\n" ); document.write( "which is answer \"A\"
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "A) . 20 B) . 57 C) . 38 D) . 23 \r
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