document.write( "Question 231700: The distance from Redding to Bishop is 400 miles. A bus leaves Redding headed to Bishop at 55 miles per hour. One hour later a bus leaves Bishop for Redding at 65 miles per hour. How far from Bishop will the two buses be when they pass? \n" ); document.write( "
Algebra.Com's Answer #171414 by stanbon(75887) ![]() You can put this solution on YOUR website! The distance from Redding to Bishop is 400 miles. \n" ); document.write( "A bus leaves Redding headed to Bishop at 55 miles per hour. \n" ); document.write( "One hour later a bus leaves Bishop for Redding at 65 miles per hour. \n" ); document.write( "How far from Bishop will the two buses be when they pass? \n" ); document.write( "------------------------------------------------ \n" ); document.write( "Reading bus DATA: \n" ); document.write( "rate = 55 mph ; distance = x mi ; time = x/55 hrs \n" ); document.write( "------------------------------------------------------- \n" ); document.write( "Bishop bus DATA: \n" ); document.write( "rate = 65 mph ; distance = 400-x ; time = (400-x)/65 hrs \n" ); document.write( "--------------------------------------------------------- \n" ); document.write( "Equation: \n" ); document.write( "Reading time - Bishop time = 1 hr \n" ); document.write( "--- \n" ); document.write( "x/55 = (400-x)/65 \n" ); document.write( "65x = 55(400-x) \n" ); document.write( "65x = 55*400 - 55x \n" ); document.write( "120x = 55*400 \n" ); document.write( "x = 550/3 miles \n" ); document.write( "--------------------- \n" ); document.write( "Distance of meeting from Bishop = 400-(550/3) = 216 2/3 miles \n" ); document.write( "=============================================================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |