document.write( "Question 30520: will a tutor please help me
\n" ); document.write( " Mary is now twice as old as Jabe.Seven years ago, the sum of their ages was 16.What are their ages now and seven years ago?
\n" ); document.write( " Mary now-
\n" ); document.write( " Jabe now-
\n" ); document.write( " Mary 7 years ago-
\n" ); document.write( " Jabe 7 years ago-
\n" ); document.write( "

Algebra.Com's Answer #17141 by checkley71(8403)\"\" \"About 
You can put this solution on YOUR website!
M+J=16 7 YEARS AGO THEREFORE TODAY THEY ARE EACH 7 YEARS OLDER THUS THEIR COMBINED AGE IS NOW 16+7+7 OR 30.\r
\n" ); document.write( "\n" ); document.write( "NOW M=2J THUS M+2M=30 OR 3M=30 OR M=10 & J=20.\r
\n" ); document.write( "\n" ); document.write( "MARY IS NOW 10 JABE IS NOW 20.\r
\n" ); document.write( "\n" ); document.write( "MARY 7 YEARS AGO WAS 3 JABE 7 YEARS AGO WAS 13.
\n" ); document.write( "
\n" );