document.write( "Question 231629: The measure of an angle is 10 less than 3 times the measure of its complement. Find the measure of both angles.\r
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document.write( "I'm doing:
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document.write( "x+y=90
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document.write( "x=3y-10
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document.write( "3y-10+y=90
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document.write( "4y-10=90
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document.write( "4y=80
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document.write( "y=20\r
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document.write( "x=3y-10
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document.write( "x=3(20)-10
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document.write( "x=60-10
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document.write( "x=50\r
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document.write( "It doesn't equal 90! Help! \n" );
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Algebra.Com's Answer #171381 by solver91311(24713)![]() ![]() You can put this solution on YOUR website! \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Absolutely on the right track. But you have got to watch your signs.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Perfect up to this point. But now you need to ADD 10 to both sides:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "John \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |