document.write( "Question 231608: two trains that are 495 mi apart travel towards each other. They pass each other 5 hrs later. If one trains is traveling half as fast as the other, what are their speed?\r
\n" ); document.write( "\n" ); document.write( "5x+5y=495
\n" ); document.write( "x=1/2-y\r
\n" ); document.write( "\n" ); document.write( "5(1/2-y)+5y=495\r
\n" ); document.write( "\n" ); document.write( "then lost\r
\n" ); document.write( "\n" ); document.write( "Thanks\r
\n" ); document.write( "\n" ); document.write( "Erika
\n" ); document.write( "

Algebra.Com's Answer #171374 by rfer(16322)\"\" \"About 
You can put this solution on YOUR website!
You have a two step problem.
\n" ); document.write( "r=D/t
\n" ); document.write( "r=495/5
\n" ); document.write( "r=99 mph total speed coming together
\n" ); document.write( "------------------------------------
\n" ); document.write( "2x+x=99
\n" ); document.write( "3x=99
\n" ); document.write( "x=33 mph
\n" ); document.write( "2x=66 mph
\n" ); document.write( "Does that help?
\n" ); document.write( "Bob
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