document.write( "Question 231608: two trains that are 495 mi apart travel towards each other. They pass each other 5 hrs later. If one trains is traveling half as fast as the other, what are their speed?\r
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document.write( "5x+5y=495
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document.write( "x=1/2-y\r
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document.write( "5(1/2-y)+5y=495\r
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document.write( "then lost\r
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document.write( "Thanks\r
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document.write( "Erika \n" );
document.write( "
Algebra.Com's Answer #171374 by rfer(16322) ![]() You can put this solution on YOUR website! You have a two step problem. \n" ); document.write( "r=D/t \n" ); document.write( "r=495/5 \n" ); document.write( "r=99 mph total speed coming together \n" ); document.write( "------------------------------------ \n" ); document.write( "2x+x=99 \n" ); document.write( "3x=99 \n" ); document.write( "x=33 mph \n" ); document.write( "2x=66 mph \n" ); document.write( "Does that help? \n" ); document.write( "Bob \n" ); document.write( " |