document.write( "Question 231104: Please answer this question : \" Three years ago, Shara was three times as old as Kaye. Three years hence she will be twice as old a Kaye. Find the present age of each. \" \n" ); document.write( "
Algebra.Com's Answer #171349 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Three years ago, Shara was three times as old as Kaye. \n" ); document.write( " Three years hence she will be twice as old a Kaye. \n" ); document.write( " Find the present age of each. \n" ); document.write( ": \n" ); document.write( "s = Sara's present age \n" ); document.write( "k = Kay's present age \n" ); document.write( "; \n" ); document.write( "Write an equation for each statement: \n" ); document.write( ": \n" ); document.write( "\" Three years ago, Shara was three times as old as Kaye. \" \n" ); document.write( "s - 3 = 3(k - 3) \n" ); document.write( "s - 3 = 3k - 9 \n" ); document.write( "s = 3k - 9 + 3 \n" ); document.write( "s = 3k -6 \n" ); document.write( ": \n" ); document.write( " \"Three years hence she will be twice as old a Kaye.\" \n" ); document.write( "s + 3 = 2(k + 3) \n" ); document.write( "s + 3 = 2k + 6 \n" ); document.write( "s = 2k + 6 - 3 \n" ); document.write( "s = 2k + 3 \n" ); document.write( ": \n" ); document.write( " Find the present age of each. \n" ); document.write( "In the above equation, replace s with (3k-6) \n" ); document.write( "3k - 6 = 2k + 3 \n" ); document.write( "3k - 2k = 3 + 6 \n" ); document.write( "k = 9 yrs is Kay's present age \n" ); document.write( "; \n" ); document.write( "I'll let you find s. \n" ); document.write( " |