document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30508>Question 30508</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I'm looking to find th 52nd term of the following harmonic series.\r<BR>\n" );
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document.write( "1+ 1/5 + 1/9 + 1/13 + 1/17 +... </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17133 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley71><B>checkley71(8403)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley71><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17133\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1 1/5 1/9 1/13 etc is adding 4 to the denominator for the next in the sequence.\r<BR>\n" );
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document.write( "Term 52 =((52-1) x 4) + 1 or 51 x 4 + 1 or 204 + 1 = 205 </SPAN>\n" );
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