document.write( "Question 231490: How many different 5-card poker hands would contain only cards of a single suit?\r
\n" ); document.write( "\n" ); document.write( "I know there are 52 cards in a deck and there are 4 different suits with 13 cards in each suit. From here, I am lost.
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Algebra.Com's Answer #171309 by Alan3354(69443)\"\" \"About 
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How many different 5-card poker hands would contain only cards of a single suit?
\n" ); document.write( "I know there are 52 cards in a deck and there are 4 different suits with 13 cards in each suit. From here, I am lost.
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\n" ); document.write( "It's 5 cards out of 13.
\n" ); document.write( "The 1st is 1 of 13, then 1 of 12, etc = 13*12*11*10*9
\n" ); document.write( "= 154,440
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\n" ); document.write( "But, since 2, 3, 4, 5, 6 is the same as 6,5,4,3,2 it's necessary to divide by 5*4*3*2*1 = 120
\n" ); document.write( "--> 154440/120 = 1287 possibilities.
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\n" ); document.write( "To be more formal, it's
\n" ); document.write( "13!/(5!*(13-5)!)
\n" ); document.write( "! is factorial. 5! = 5*4*3*2*1, etc.
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