document.write( "Question 231490: How many different 5-card poker hands would contain only cards of a single suit?\r
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document.write( "I know there are 52 cards in a deck and there are 4 different suits with 13 cards in each suit. From here, I am lost. \n" );
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Algebra.Com's Answer #171309 by Alan3354(69443)![]() ![]() You can put this solution on YOUR website! How many different 5-card poker hands would contain only cards of a single suit? \n" ); document.write( "I know there are 52 cards in a deck and there are 4 different suits with 13 cards in each suit. From here, I am lost. \n" ); document.write( "----------------- \n" ); document.write( "It's 5 cards out of 13. \n" ); document.write( "The 1st is 1 of 13, then 1 of 12, etc = 13*12*11*10*9 \n" ); document.write( "= 154,440 \n" ); document.write( "---------- \n" ); document.write( "But, since 2, 3, 4, 5, 6 is the same as 6,5,4,3,2 it's necessary to divide by 5*4*3*2*1 = 120 \n" ); document.write( "--> 154440/120 = 1287 possibilities. \n" ); document.write( "----------------- \n" ); document.write( "To be more formal, it's \n" ); document.write( "13!/(5!*(13-5)!) \n" ); document.write( "! is factorial. 5! = 5*4*3*2*1, etc. \n" ); document.write( " \n" ); document.write( " |