document.write( "Question 231456: If the length of each edge of a cube is increased by 75%, by what percent is the surface area of the original cube increased? \n" ); document.write( "
Algebra.Com's Answer #171300 by Theo(13342)\"\" \"About 
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Surface area of the original cube is equal to 6 * s^2\r
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\n" ); document.write( "\n" ); document.write( "If you increase each s by 75%, then each s becomes 1.75 * s.\r
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\n" ); document.write( "\n" ); document.write( "The surface area then becomes 6 * (1.75 * s)^2\r
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\n" ); document.write( "\n" ); document.write( "This is equivalent to 6 * 1.75^2 * s^2.\r
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\n" ); document.write( "\n" ); document.write( "This equals to 18.375 * s^2\r
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\n" ); document.write( "\n" ); document.write( "Since the original surface area equals 6 * s^2, and the new surface area = 18.375 * s^2, then the new surface area is equal to 3.0625 times the original surface area.\r
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\n" ); document.write( "\n" ); document.write( "This would be 306.25% of the original surface area which would be an increase of 206.5% of the original surface area.\r
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\n" ); document.write( "\n" ); document.write( "To see if this is accurate, use some numbers and see if the percentages work out.\r
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\n" ); document.write( "\n" ); document.write( "Let s = 15\r
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\n" ); document.write( "\n" ); document.write( "6 * 15^2 = a surface area of 1350.\r
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\n" ); document.write( "\n" ); document.write( "Increase s by 75%.\r
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\n" ); document.write( "\n" ); document.write( "s goes from 15 to 15 + .75 * 15 = 26.25\r
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\n" ); document.write( "\n" ); document.write( "New Surface area is 26.25^2 * 6 = 4134.375\r
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\n" ); document.write( "\n" ); document.write( "Divide 4134.375 by 1350 to get 3.0625\r
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\n" ); document.write( "\n" ); document.write( "4134.375 is equal to 3.0625 times 1350 which is an increase of 206.25%\r
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\n" ); document.write( "\n" ); document.write( "Take 206.25% of 1350 and add it to 1350 to get 4134.375.\r
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\n" ); document.write( "\n" ); document.write( "It all checks out.\r
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\n" ); document.write( "\n" ); document.write( "Your answer is that the surface area of the original cube is increased by 206.25%\r
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