document.write( "Question 231453: Amy drove the 200 miles to New Orleans at an average speed 10 miles per hour faster than her usual average speed. If she completed the trip in 1 hour less than usual, what is her usual driving speed in miles per hour.\r
\n" ); document.write( "\n" ); document.write( "I know the answer is 40 miles per hour, but how did they come up with this? I think there is numbers missing in this problem.
\n" ); document.write( "Thank you,
\n" ); document.write( "Katie
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Algebra.Com's Answer #171296 by Theo(13342)\"\" \"About 
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distance = 200 miles
\n" ); document.write( "Her usual speed is X miles per hour since we don't know it.
\n" ); document.write( "Her usual time is T hours because we don't know that either.\r
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\n" ); document.write( "\n" ); document.write( "Problem states that she traveled 10 miles per hour faster than her usual speed.\r
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\n" ); document.write( "\n" ); document.write( "This makes the speed she traveled at equal to X + 10.\r
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\n" ); document.write( "\n" ); document.write( "Problem states that she took 1 hour less.\r
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\n" ); document.write( "\n" ); document.write( "This makes the time she took equal to T - 1.\r
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\n" ); document.write( "\n" ); document.write( "She normally travels at X miles per hours and takes T hours.\r
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\n" ); document.write( "\n" ); document.write( "Since rate * time = distance, we get:\r
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\n" ); document.write( "\n" ); document.write( "X * T = 200\r
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\n" ); document.write( "\n" ); document.write( "This time she traveled 10 miles per hour faster and took 1 hour less.\r
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\n" ); document.write( "\n" ); document.write( "This time, we get:\r
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\n" ); document.write( "\n" ); document.write( "(X+10) * (T-1) = 200\r
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\n" ); document.write( "\n" ); document.write( "Since they are both equal to 200, then they are both equal to each other, so we get:\r
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\n" ); document.write( "\n" ); document.write( "X*T = (X+10)*(T-1)\r
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\n" ); document.write( "\n" ); document.write( "We simplify this by multiplying out all terms to get:\r
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\n" ); document.write( "\n" ); document.write( "X*T = X*T - X + 10T - 10\r
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\n" ); document.write( "\n" ); document.write( "We have one equation in two unknowns, but we can substitute for one of the unknowns and solve for the other.\r
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\n" ); document.write( "\n" ); document.write( "We'll take the equation X*T = 200 and solve for T to get T = 200/X\r
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\n" ); document.write( "\n" ); document.write( "We'll then replace T in our equation of X*T = X*T - X + 10T - 10 to get:\r
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\n" ); document.write( "\n" ); document.write( "X*200/X = X*200/X - X + 10*200/X - 10.\r
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\n" ); document.write( "\n" ); document.write( "We'll simplify this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "200 = 200 - X + 2000/X - 10.\r
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\n" ); document.write( "\n" ); document.write( "We'll subtract 200 and we'll add X and we'll subtract 2000/X and we'll add 10 to both sides of this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "X - 2000/X + 10 = 0\r
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\n" ); document.write( "\n" ); document.write( "We'll multiply both sides of this equation by X to get:\r
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\n" ); document.write( "\n" ); document.write( "X^2 + 10X - 2000 = 0\r
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\n" ); document.write( "\n" ); document.write( "This factors out to:\r
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\n" ); document.write( "\n" ); document.write( "(X-40) * (X+50) = 0\r
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\n" ); document.write( "\n" ); document.write( "X can be either 40 or -50.\r
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\n" ); document.write( "\n" ); document.write( "since X can't be negative, we are left with X = 40.\r
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\n" ); document.write( "\n" ); document.write( "Since X*T = 200, We get T = 5\r
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\n" ); document.write( "\n" ); document.write( "Our answer is:\r
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\n" ); document.write( "\n" ); document.write( "X = 40
\n" ); document.write( "T = 5\r
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\n" ); document.write( "\n" ); document.write( "40*5 = 200 which is the normal time at the normal rate.\r
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\n" ); document.write( "\n" ); document.write( "50*4 = 200 which is 1 hour less than the normal time at 10 miles per hour more than the normal rate.\r
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