document.write( "Question 231441: x-3z = -2
\n" ); document.write( "3x + y - 2z = 5
\n" ); document.write( "2x + 2y + z = 4\r
\n" ); document.write( "\n" ); document.write( "could some one help me please \n" ); document.write( "

Algebra.Com's Answer #171295 by algebrapro18(249) $\"\"$ $\"About$

You can put this solution on YOUR website!
You can either solve the system by back substitution or elimination. I chose to solve it by substitution. \r
\n" ); document.write( "\n" ); document.write( "So we solve the first equation for x and get x = -2+3z. Now we can substitute that into the other equations. I'll leave the algebra for you to do but you will end up with:\r
\n" ); document.write( "\n" ); document.write( "y+7z=11
\n" ); document.write( "2y+7z=8\r
\n" ); document.write( "\n" ); document.write( "And now we can solve the system of 2 equations and 2 unknowns. Again I chose to do this by substitution but elimination would work as well. I solved the top equation for y and got y=11-7z. Then plugged that into the bottom equation so I could solve for z. Again I'll leave the algebra for you to do but you should get z = 2. Then you substitute that into your equation for y and end up with y = -3. Then the value in for z into the equation for x and you will see that x = 4. \r
\n" ); document.write( "\n" ); document.write( "So your final solution is (4,-3,2). \n" ); document.write( "

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