document.write( "Question 231428: An automobile manufacturer can produce up to 300 cars per day. The profit made from the sale of these vehicles can be modeled by the function \"P%28x%29=-10x%5E2%2B3500x-66000\" Where P(x) is the profit in dollars and x is the number of automobiles made and sold. How many cars should be made and sold to maximize profits. \n" ); document.write( "
Algebra.Com's Answer #171287 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
What you have is a quadratic formula in the form of ax^2 + bx + c where:\r
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\n" ); document.write( "\n" ); document.write( "a = -10
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\n" ); document.write( "c = -66000\r
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\n" ); document.write( "\n" ); document.write( "Since a is negative, this quadratic equation opens downward.\r
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\n" ); document.write( "\n" ); document.write( "The max point is at x = -b/2a\r
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\n" ); document.write( "\n" ); document.write( "That would be at x = -3500/-20 = 175.\r
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\n" ); document.write( "\n" ); document.write( "When x = 175, y = -10*175^2 + 3500*175 - 66000 = 240250\r
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\n" ); document.write( "\n" ); document.write( "Maximum profit attained is $240250.\r
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\n" ); document.write( "\n" ); document.write( "This happens when 175 cars are sold.\r
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\n" ); document.write( "\n" ); document.write( "graph of this equation looks like this:\r
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\n" ); document.write( "\n" ); document.write( "\"graph%28400%2C400%2C-50%2C350%2C-100000%2C300000%2C-10x%5E2%2B3500x-66000%2C240250%29\"\r
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\n" ); document.write( "\n" ); document.write( "As can be seen, the graph peaks at x = 175.\r
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