document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=231426>Question 231426</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the perimeter of a triangle if one side is 11 centimeters, another side is two-fifths the perimeter and the third side is one half the perimeter. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #171280 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=171280\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, <BR>\n" );
document.write( "Let x be the total perimeter,then we can set up an equation.<BR>\n" );
document.write( "11 + 2/5(x) + 1/2(x) = x   Let's multiply 10 so to get rid of the fractions. <BR>\n" );
document.write( "110 + 4x + 5x = 10x        Now, subtract 9x from both sides.<BR>\n" );
document.write( "110 = x                    This gives us the total perimeter. <BR>\n" );
document.write( "11 cm is one side (given)<BR>\n" );
document.write( "44 cm is another side<BR>\n" );
document.write( "55 cm is the other side    These should add up to 110 cm<BR>\n" );
document.write( "RJ<BR>\n" );
document.write( "www.math-unlock.com<BR>\n" );
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