document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=231414>Question 231414</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A chemical storeroom has an 80% alcohol solution and a 30% alcohol solution.  How many milliliters of each should be used to obtain 50 milliliters of a 60% solution. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #171276 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=171276\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = amount of 80% solution<BR>\n" );
document.write( "50-x= amount of 30% solution<BR>\n" );
document.write( "50 = number of milliliters  of 60%\r<BR>\n" );
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document.write( ".80x+.30(50-x)=.60*50<BR>\n" );
document.write( ".80x+15-.30x=30<BR>\n" );
document.write( ".50x+15=30<BR>\n" );
document.write( ".50x=15<BR>\n" );
document.write( "x=15/.50=30 milliliters of 80%<BR>\n" );
document.write( "50-x=20 milliliters of 30%\r<BR>\n" );
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document.write( "Dr. Robert J. Rapalje </SPAN>\n" );
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