document.write( "Question 231237: Word Problem Five - On a 570 mile trip, Andy averaged 5 mph faster for the last
\n" ); document.write( "240 miles than he did for the first 330 miles. The entire trip took 10 hours.
\n" ); document.write( "How fast did he travel for the first 330 miles? (Show a complete algebraic
\n" ); document.write( "solution for the problem and check the answer.\r
\n" ); document.write( "\n" ); document.write( "I drew a picture first.. then i thought that the mph for the first 330 miles is x? and for the second 240 miles was x+5? Im so confused on how to calculate the 10 hours part in...:( \r
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Algebra.Com's Answer #171233 by checkley77(12844)\"\" \"About 
You can put this solution on YOUR website!
D=RT or T=D/R
\n" ); document.write( "10=330/X+240/(X+5)
\n" ); document.write( "10=(330*(X+5)+240X)/X(X+5)
\n" ); document.write( "10=(330X+1,650+240X)/(X^2+5X)
\n" ); document.write( "10(X^2+5X)=570X+1,650
\n" ); document.write( "10X^2+50X-570X-1,650=0
\n" ); document.write( "10X^2-520X-1,650=0
\n" ); document.write( "10(X^2-52X-165)=0
\n" ); document.write( "10(X-55)(X+3)=0
\n" ); document.write( "X-55=0
\n" ); document.write( "X=55 MPH FOR THE 330 MILE TRIP.
\n" ); document.write( "55+5=60 MPH FOR THE 240 MILE TRIP.
\n" ); document.write( "PROOF:
\n" ); document.write( "10=330/55+240/60
\n" ); document.write( "10=6+4
\n" ); document.write( "10=10
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