document.write( "Question 231274: the length of a rectangle is 4ft more than twice the with. The area of the rectangle is 48ft squared. Find the length and width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #171218 by checkley77(12844)\"\" \"About 
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Area=LW
\n" ); document.write( "L=2W+4
\n" ); document.write( "48=(2W+4)W
\n" ); document.write( "48=2W^2+4W
\n" ); document.write( "2W^2+4W-48=0
\n" ); document.write( "2(W^2+2W-24)=0
\n" ); document.write( "2(W+6)(W-4)=0
\n" ); document.write( "W-4=0
\n" ); document.write( "W=4 ANS FOR THE WIDTH.
\n" ); document.write( "L=2*4+4
\n" ); document.write( "L=8+4
\n" ); document.write( "L=12 ANS. FOR THE LENGTH.
\n" ); document.write( "PROOF:
\n" ); document.write( "48=12*4
\n" ); document.write( "48=48
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