document.write( "Question 231274: the length of a rectangle is 4ft more than twice the with. The area of the rectangle is 48ft squared. Find the length and width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #171218 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! Area=LW \n" ); document.write( "L=2W+4 \n" ); document.write( "48=(2W+4)W \n" ); document.write( "48=2W^2+4W \n" ); document.write( "2W^2+4W-48=0 \n" ); document.write( "2(W^2+2W-24)=0 \n" ); document.write( "2(W+6)(W-4)=0 \n" ); document.write( "W-4=0 \n" ); document.write( "W=4 ANS FOR THE WIDTH. \n" ); document.write( "L=2*4+4 \n" ); document.write( "L=8+4 \n" ); document.write( "L=12 ANS. FOR THE LENGTH. \n" ); document.write( "PROOF: \n" ); document.write( "48=12*4 \n" ); document.write( "48=48 \n" ); document.write( " \n" ); document.write( " |