document.write( "Question 231290: shiela invests part of part of$6000 at 6% interest and the other part at 11% interest. Her total annual income from these investments is $460. How much is investes at each rate? \n" ); document.write( "
Algebra.Com's Answer #171214 by rfer(16322)![]() ![]() ![]() You can put this solution on YOUR website! .06x+.11(6000-x)=460 \n" ); document.write( ".06x+660-.11x=460 \n" ); document.write( "-.05x=-200 \n" ); document.write( "x=$4000 at 6% \n" ); document.write( "$2000 at 11% \n" ); document.write( " |