document.write( "Question 231290: shiela invests part of part of$6000 at 6% interest and the other part at 11% interest. Her total annual income from these investments is $460. How much is investes at each rate? \n" ); document.write( "
Algebra.Com's Answer #171214 by rfer(16322)\"\" \"About 
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.06x+.11(6000-x)=460
\n" ); document.write( ".06x+660-.11x=460
\n" ); document.write( "-.05x=-200
\n" ); document.write( "x=$4000 at 6%
\n" ); document.write( "$2000 at 11%
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