document.write( "Question 30478: how whould I solve the equations 6x-2y=10 and x-2y= negtive 5 by using the subtution method? \n" ); document.write( "
Algebra.Com's Answer #17120 by sdmmadam@yahoo.com(530)\"\" \"About 
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solve the equations 6x-2y=10 and x-2y= negtive 5 by using the subtution method?\r
\n" ); document.write( "\n" ); document.write( "6x-2y =10 ----(1)
\n" ); document.write( "x-2y = - 5 ----(2)
\n" ); document.write( "Observe that(2) contains (1)x and hence it is easy find x in terms of y using(2)
\n" ); document.write( "From (2), we have
\n" ); document.write( "x = 2y-5 ----(*)
\n" ); document.write( "Putting (*) in (1), that is substituting for x in (1), we get
\n" ); document.write( "6(2y-5)-2y = 10
\n" ); document.write( "12y-30-2y = 10
\n" ); document.write( "(12y-2y)=10+30 (grouping like terms,changing sign while changing side)
\n" ); document.write( "10y = 40
\n" ); document.write( "y = 40/10 = 4
\n" ); document.write( "Putting y = 4 in (*), we have
\n" ); document.write( "x = 2y -5 = 2X4 - 5 = 8-5 = 3
\n" ); document.write( "Answer x = 3 and y= 4
\n" ); document.write( "Verification: Since we used (*)which is nothing but (2)for finding x using y,
\n" ); document.write( "we shall use (1)for verification.
\n" ); document.write( "x = 3 and y =4 in 6x-2y =10 ----(1)
\n" ); document.write( "LHS = 6x-2y = 6X3-2X4 = 18-8 = 10 = RHS
\n" ); document.write( "Therefore our values are correct
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