document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=231205>Question 231205</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the number N, in millions, of broadband cable and DSL subscribers in the United States t yearsafter 1998 cane be approximated by<BR>\n" );
document.write( "N = 0.3t^2 + 0.6t<BR>\n" );
document.write( "When will there be 36 million brodband cable and DSL subscribers?\r<BR>\n" );
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document.write( "Thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #171196 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley77><B>checkley77(12844)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley77><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=171196\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> N = 0.3t^2 + 0.6t<BR>\n" );
document.write( "36=.3t^2+.6t<BR>\n" );
document.write( ".3t^2+.6t-36=0<BR>\n" );
document.write( "(.3t-3)(t+12)=0<BR>\n" );
document.write( ".3t-3=0<BR>\n" );
document.write( ".3t=3<BR>\n" );
document.write( "t=3/.3<BR>\n" );
document.write( "t=10 years after 1998 or the year 2008 there will be 36 million subscribers.<BR>\n" );
document.write( "Proof:<BR>\n" );
document.write( "36=.3*10^2+.6^10<BR>\n" );
document.write( "36=30+6<BR>\n" );
document.write( "36=36 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );