document.write( "Question 231261: 2(x-14)+3x-4x(x-9)=10x+8 \n" ); document.write( "
Algebra.Com's Answer #171194 by texttutoring(324)\"\" \"About 
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2(x-14)+3x-4x(x-9)=10x+8\r
\n" ); document.write( "\n" ); document.write( "You first need to get rid of the brackets by using distribution:\r
\n" ); document.write( "\n" ); document.write( "2x-28+3x-4x^2+36x=10x+8\r
\n" ); document.write( "\n" ); document.write( "Then set the right-hand side to zero:\r
\n" ); document.write( "\n" ); document.write( "2x-28+3x-4x^2+36x=10x+8-10x-8
\n" ); document.write( "2x-28+3x-4x^2+36x-10x-8=0\r
\n" ); document.write( "\n" ); document.write( "Now collect like terms:\r
\n" ); document.write( "\n" ); document.write( "-4x^2+31x-36=0\r
\n" ); document.write( "\n" ); document.write( "Now divide everything by -1:\r
\n" ); document.write( "\n" ); document.write( "4x^2-31x+36=0\r
\n" ); document.write( "\n" ); document.write( "Use the quadratic formula to find:\r
\n" ); document.write( "\n" ); document.write( "x=6.33 or x=1.42
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