document.write( "Question 231140: PLease help me solve; If the width of a rectangle is 1 inch less than its length and the diagonal is 1 inch longer than its length, find the length and the width. I know w=l-1 and D=l+1 but I dont know how to fill in the blanks to solve the problem \n" ); document.write( "
Algebra.Com's Answer #171159 by checkley77(12844)\"\" \"About 
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SUGGESTION:USE THE CAPITAL L SO YOU WON'T GET CONFUSED WITH THE SMALL l & THE 1.
\n" ); document.write( "W=L-1
\n" ); document.write( "D=L+1
\n" ); document.write( "L^2+W^2=D^2
\n" ); document.write( "L^2+(L-1)^2=(L+1)^2
\n" ); document.write( "L^2+L^2-2L+1=L^2+2L+1
\n" ); document.write( "2L^2-L^2-2L-2L+1-1=0
\n" ); document.write( "L^2-4L=0
\n" ); document.write( "L(L-4)=0
\n" ); document.write( "L-4=0
\n" ); document.write( "L=4 ANS. FOR THE LENGTH.
\n" ); document.write( "W=4-1=3 ANS. FOR THE WIDTH.
\n" ); document.write( "D=4+1=5 ANS. FOR THE DIAGONAL.
\n" ); document.write( "PROOF:
\n" ); document.write( "4^2+3^2=5^2
\n" ); document.write( "16+9=25
\n" ); document.write( "25=25
\n" ); document.write( " \n" ); document.write( "
\n" );