document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=231194>Question 231194</A>: <I><SPAN STYLE=\"word-break: break-all;\"> This is a rational equation. 4 over X plus seven equals 2 over three X </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #171145 by </B><A HREF=/tutors/aboutme.mpl?userid=unlockmath><B>unlockmath(1688)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=unlockmath><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=unlockmath><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=171145\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hello, \r<BR>\n" );
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document.write( "Let's write the equation out like this:\r<BR>\n" );
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document.write( "              4/(x+7)= 2/3x\r<BR>\n" );
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document.write( "Let's remove the denominators on each side by multiplying (3x)(x+7)<BR>\n" );
document.write( "This will leave us with: \r<BR>\n" );
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document.write( "                          4(3x) = 2(x + 7)\r<BR>\n" );
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document.write( "or rewritten               12x = 2x + 14\r<BR>\n" );
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document.write( "Move 2x by subtracting both sides\r<BR>\n" );
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document.write( "                           10x = 14\r<BR>\n" );
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document.write( "Divide each side by 10\r<BR>\n" );
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document.write( "                             x = 14/10  reduce it to 7/5 or 1  2/5\r<BR>\n" );
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document.write( "RJ Toftness <BR>\n" );
document.write( "www.math-unlock.com </SPAN>\n" );
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