document.write( "Question 231170: Solve problem by completing the square, leaving the results in simplest radical form Check.\r
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document.write( "I am confused with this one:\r
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document.write( "3xsquared - 6x =3
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document.write( "divide by 3
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document.write( "x squared - 3x = 9
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document.write( "x squared - 2x = 1 (Add one to both sides)......x squared -2x + 1 = 4
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document.write( "now I am lost....please help me! Thanks \n" );
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Algebra.Com's Answer #171140 by Theo(13342)![]() ![]() You can put this solution on YOUR website! Your equation is:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3x^2 - 6x = 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You need to divide both sides of this equation by 3 to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x^2 - 2x = 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You take 1/2 of 2 to get 1.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your factors are (x-1)^2 = 1 + 1\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This becomes (x-1)^2 = 2\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Take the square root of this to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x-1 = +/- sqrt(2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Add 1 to both sides to get:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 1 +/- sqrt(2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This means that:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 1+sqrt(2) \n" ); document.write( "or: \n" ); document.write( "x = 1-sqrt(2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "To see if this works out ok, you need to substitute in the original equation to see if the equation is true.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your original equation is 3x^2 - 6x = 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "If x = 1 + sqrt(2), this becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3 * (1+sqrt(2)^2) - 6 * (1+sqrt(2)) = 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This becomes:\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "3 + 6*sqrt(2) + 6 - 6 - 6*sqrt(2) = 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "6 and 6*sqrt(2) cancel out leaving 3 = 3\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "This is true so the value for x is good.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'll leave you to replace x with 1 - sqrt(2) to see if that's good too.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "You might want to check out the following website to review how to complete the square.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Completing the Square (algebrahelp)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |