document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=30467>Question 30467</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me work this problem.  I have the answer but don't know how to work it.  Please explain in very plain English terms!  \r<BR>\n" );
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document.write( "Point A (-4,1) is in the standard (x,y) coordinate plane.  What must be the coordinates of Point B so that the line x = 2 is the perpendicular bisector of  AB ?  (note: there is a line over AB)  Thank you for your help...Karen </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #17114 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=17114\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Point A (-4,1) is in the standard (x,y) coordinate plane.  What must be the coordinates of Point B so that the line x = 2 is the perpendicular bisector of  AB ?  (note: there is a line over AB)  Thank you for your help...Karen<BR>\n" );
document.write( "LINE X=2 IS PARALLEL TO Y AXIS SO ITS PERPENDICULAR WOULD BE PARALLEL TO X AXIS<BR>\n" );
document.write( "HENCE ITS EQUATION SHALL BE Y=K......THAT IS EQN.OF AB SHALL BE Y=CONSTANT<BR>\n" );
document.write( "FURTHER X=2 BISECTS AB.HENCE MID POINT OF AB SHALL BE ON X=2<BR>\n" );
document.write( "THAT IS X COORDINATE OF MIDPOINT SHALL BE EQUAL TO 2.IF WE TAKE POINT B AS (P,Q)<BR>\n" );
document.write( "THEN X COORDINATE OF MID POINT OF AB SHALL BE = (-4+P)/2=2<BR>\n" );
document.write( "-4+P=4<BR>\n" );
document.write( "P=8<BR>\n" );
document.write( "WE SPROVED EARLIER THAT EQN OF AB SHALL BE IN THE FORM Y=CONSTANT..OR ITS SLOPE IS ZERO SINCE Y=CONSTANT MEANS ...Y=0*X+CONSTANT<BR>\n" );
document.write( "SLOPE OF AB =(Q-1)/(P-(-4))=0...SO Q-1=0...SO Q=1...<BR>\n" );
document.write( "HENCE POINT B IS (8,1)<BR>\n" );
document.write( "YOU WILL SEE ITS EQN. IS Y=1..TO UNDERSTAND HOW THEY LOOK LIKE SEE THE GRAPH BELOW\r<BR>\n" );
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