document.write( "Question 231172: a group of friends went out to dinner and had a bill that totaled $288. WHen it came time to split the total cost of the bill equally, each person who was left (2 people left early) had to pay an extra $4.80 on top of their own part to cover the price of the two missing people. How many people were in the original dinner group? \n" ); document.write( "
Algebra.Com's Answer #171122 by stanbon(75887) ![]() You can put this solution on YOUR website! a group of friends went out to dinner and had a bill that totaled $288. WHen it came time to split the total cost of the bill equally, each person who was left (2 people left early) had to pay an extra $4.80 on top of their own part to cover the price of the two missing people. How many people were in the original dinner group? \n" ); document.write( "--------------- \n" ); document.write( "Let the original number in the group be \"x\": \n" ); document.write( "Original average cost was 288/x dollars \n" ); document.write( "------------------- \n" ); document.write( "After two left there were \"x-2\" in the grou: \n" ); document.write( "New average cost was 288/(x-2) dollars \n" ); document.write( "---------------------------------------------- \n" ); document.write( "Equation \n" ); document.write( "New average - old average = 4.80 dollars \n" ); document.write( "288/(x-2) - 288/x = 4.8 \n" ); document.write( "Divide thru by 4.8 to get: \n" ); document.write( "60/(x-2) - 60/x = 1 \n" ); document.write( "60x - 60(x-2) = x(x-2) \n" ); document.write( "120 = x^2-2x \n" ); document.write( "x^2-2x-120 = 0 \n" ); document.write( "(x-12)(x+10) = 0 \n" ); document.write( "Positive solution: \n" ); document.write( "x = 12 (original number in the group) \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " \n" ); document.write( " |