document.write( "Question 231172: a group of friends went out to dinner and had a bill that totaled $288. WHen it came time to split the total cost of the bill equally, each person who was left (2 people left early) had to pay an extra $4.80 on top of their own part to cover the price of the two missing people. How many people were in the original dinner group? \n" ); document.write( "
Algebra.Com's Answer #171122 by stanbon(75887)\"\" \"About 
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a group of friends went out to dinner and had a bill that totaled $288. WHen it came time to split the total cost of the bill equally, each person who was left (2 people left early) had to pay an extra $4.80 on top of their own part to cover the price of the two missing people. How many people were in the original dinner group?
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\n" ); document.write( "Let the original number in the group be \"x\":
\n" ); document.write( "Original average cost was 288/x dollars
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\n" ); document.write( "After two left there were \"x-2\" in the grou:
\n" ); document.write( "New average cost was 288/(x-2) dollars
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\n" ); document.write( "Equation
\n" ); document.write( "New average - old average = 4.80 dollars
\n" ); document.write( "288/(x-2) - 288/x = 4.8
\n" ); document.write( "Divide thru by 4.8 to get:
\n" ); document.write( "60/(x-2) - 60/x = 1
\n" ); document.write( "60x - 60(x-2) = x(x-2)
\n" ); document.write( "120 = x^2-2x
\n" ); document.write( "x^2-2x-120 = 0
\n" ); document.write( "(x-12)(x+10) = 0
\n" ); document.write( "Positive solution:
\n" ); document.write( "x = 12 (original number in the group)
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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