document.write( "Question 231173: x/3 = 4/x + 1 \n" ); document.write( "
Algebra.Com's Answer #171116 by stanbon(75887)\"\" \"About 
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x/3 = 4/x + 1
\n" ); document.write( "-------
\n" ); document.write( "Multiply thru by 3x to get:
\n" ); document.write( "x^2 = 12 + 3x
\n" ); document.write( "Rearrange:
\n" ); document.write( "x^2-3x-12 = 0
\n" ); document.write( "Use the Quadratic formula:
\n" ); document.write( "x = [3 +- sqrt(9 - 4*1*-12)]/2
\n" ); document.write( "---
\n" ); document.write( "x = [3 +- sqrt(57)]/2
\n" ); document.write( "---
\n" ); document.write( "x = [3 + sqrt(57)]/2 or x = [3 - sqrt(57)]/2
\n" ); document.write( "===============================================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "
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