document.write( "Question 230220: 2y^-2 -3y^-1 -2 =0\r
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Algebra.Com's Answer #171088 by troymuga(3)\"\" \"About 
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2/(y^2) - 3/y = 2
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\n" ); document.write( "2/y - 3 = 2y
\n" ); document.write( "Switch'em around
\n" ); document.write( "2/y - 2y = 3
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\n" ); document.write( "2 - 2y^2 = 3y
\n" ); document.write( "ARRANGE THEM TO ONE SIDE
\n" ); document.write( "2y^2 +3y - 2
\n" ); document.write( "FACTOR the POLYNOMIAL
\n" ); document.write( "(2y - 1)(y + 2) = 0
\n" ); document.write( "SOLVE for y
\n" ); document.write( "y = 1/2, y = -2
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