document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=231095>Question 231095</A>: <I><SPAN STYLE=\"word-break: break-all;\"> please help me with this. i would appreciate it very much.\r<BR>\n" );
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document.write( "1-2/x=14/3x-1/3\r<BR>\n" );
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document.write( "thank you!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #171082 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=171082\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1-2/x=14/3x-1/3<BR>\n" );
document.write( "Is it 1 - (2/x) = 14/(3x) - 1/3 ??  If so:<BR>\n" );
document.write( "Multiply thru by 3x<BR>\n" );
document.write( "3x - 6 = 14 - x<BR>\n" );
document.write( "4x = 20<BR>\n" );
document.write( "x = 5<BR>\n" );
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