document.write( "Question 30354: Question:
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document.write( "Factor: 2x^4-5x^3-10x^2+15x+18\r
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document.write( "(a) (2x-3) (x+1) (x+2) (x-3)
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document.write( "(b) 2x+3) (x-1) (x-2) (x+3)
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document.write( "(c) (2x+3) (x+1) (x-2) (x-3)
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document.write( "(d) (2x-3) (x-1) (x+2) (x+3)\r
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document.write( "Thank you \n" );
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Algebra.Com's Answer #17107 by sdmmadam@yahoo.com(530)![]() ![]() ![]() You can put this solution on YOUR website! Let f(x) = 2x^4-5x^3-10x^2+15x+18 = 0 \n" ); document.write( "Trying values by inspection \n" ); document.write( "x = -1, 2 ,3 and (-3/2) hold \n" ); document.write( "Therefore [x-(-1)], (x-2), (x-3) and (2x+3) are the factors \n" ); document.write( "Hence 2x^4-5x^3-10x^2+15x+18 = (2x+3) (x+1) (x-2) (x-3) \n" ); document.write( "Therefore choice (c) (2x+3) (x+1) (x-2) (x-3) is correct \n" ); document.write( "Remark: So much is the answer if the question is a 1 mark - marking the right answer question. \n" ); document.write( "If it carries more marks, then the steps are \n" ); document.write( "By inspection x = -1 is a root of f(x) = 0 \n" ); document.write( "This means (x+1) is a factor \n" ); document.write( "On long division of (2x^4-5x^3-10x^2+15x+18 ) by (x+1) \n" ); document.write( "You get (2x^3-7x^2-3x+18)=g(x) say \n" ); document.write( "By inspection x = 2 is a root of g(x) = 0 \n" ); document.write( "This means (x-2) is a factor \n" ); document.write( "On long division of (2x^3-7x^2-3x+18)by (x-2) \n" ); document.write( "you get (2x^2-3x-9) \n" ); document.write( "And (2x^2-3x-9)= (x-3)(2x+3) \n" ); document.write( "Therefore 2x^4-5x^3-10x^2+15x+18 = (2x+3) (x+1) (x-2) (x-3) which is choice (c)\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |