document.write( "Question 231035: A student normally needs 15 seconds for a 100 m sprint
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document.write( "One day favorable wind conditions help her to increase her speed by 2 km/h
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document.write( "What is her time now? \n" );
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Algebra.Com's Answer #171067 by edjones(8007)![]() ![]() You can put this solution on YOUR website! st=d \n" ); document.write( "15s=100 \n" ); document.write( "s=100/15 \n" ); document.write( "=20/3 m/sec \n" ); document.write( ". \n" ); document.write( "2km/h \n" ); document.write( "=2000/60^2 \n" ); document.write( "=2000/3600 \n" ); document.write( "=20/36 \n" ); document.write( "=5/9 m/sec \n" ); document.write( ". \n" ); document.write( "20/3 + 5/9 \n" ); document.write( "=60/9 + 5/9 \n" ); document.write( "=65/9 m/sec new speed. \n" ); document.write( ". \n" ); document.write( "65t/9=100 \n" ); document.write( "t=900/65=180/13 sec \n" ); document.write( "=13.85 sec \n" ); document.write( ". \n" ); document.write( "Ed \n" ); document.write( ". \n" ); document.write( " |