document.write( "Question 230809: A rectangle has dimensions of 60 by 40. The longer sides of the rectangle increase
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document.write( "by 20%, and the shorter sides decrease by 20% to create a new rectangle. Find the
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document.write( "ratio of the new rectangle’s perimeter to the old rectangle’s perimeter. \n" );
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Algebra.Com's Answer #171042 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A rectangle has dimensions of 60 by 40. \n" ); document.write( " The longer sides of the rectangle increase by 20%, \n" ); document.write( " and the shorter sides decrease by 20% to create a new rectangle. \n" ); document.write( " Find the ratio of the new rectangle’s perimeter to the old rectangle’s perimeter. \n" ); document.write( ": \n" ); document.write( "Find the original rectangles perimeter \n" ); document.write( "P = 2(60) + 2(40) \n" ); document.write( "P = 200 \n" ); document.write( ": \n" ); document.write( "Longer side increase of 20% \n" ); document.write( "1.2*60 = 72 \n" ); document.write( "shorter side decrease of 20% \n" ); document.write( ".8*40 = 32 \n" ); document.write( ": \n" ); document.write( "New perimeter \n" ); document.write( "p = 2(72) + 2(32) \n" ); document.write( "p = 208 \n" ); document.write( ": \n" ); document.write( "Ratio new p to old p: \n" ); document.write( " |