document.write( "Question 230809: A rectangle has dimensions of 60 by 40. The longer sides of the rectangle increase
\n" ); document.write( "by 20%, and the shorter sides decrease by 20% to create a new rectangle. Find the
\n" ); document.write( "ratio of the new rectangle’s perimeter to the old rectangle’s perimeter.
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Algebra.Com's Answer #171042 by ankor@dixie-net.com(22740)\"\" \"About 
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A rectangle has dimensions of 60 by 40.
\n" ); document.write( " The longer sides of the rectangle increase by 20%,
\n" ); document.write( " and the shorter sides decrease by 20% to create a new rectangle.
\n" ); document.write( " Find the ratio of the new rectangle’s perimeter to the old rectangle’s perimeter.
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\n" ); document.write( "Find the original rectangles perimeter
\n" ); document.write( "P = 2(60) + 2(40)
\n" ); document.write( "P = 200
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\n" ); document.write( "Longer side increase of 20%
\n" ); document.write( "1.2*60 = 72
\n" ); document.write( "shorter side decrease of 20%
\n" ); document.write( ".8*40 = 32
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\n" ); document.write( "New perimeter
\n" ); document.write( "p = 2(72) + 2(32)
\n" ); document.write( "p = 208
\n" ); document.write( ":
\n" ); document.write( "Ratio new p to old p:
\n" ); document.write( "\"208%2F200\" = \"26%2F25\"
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