document.write( "Question 230904: An express and local train leave Grayslake at 3pm and head for chicago 50 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the speed of each train.\r
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document.write( "I have this set up I think ok but thats about as far as I get
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document.write( " rate time distance
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document.write( "Local x t 50
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document.write( "Express x(2) t -1 50 \n" );
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Algebra.Com's Answer #171005 by checkley77(12844) ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "50=R(T-1) \n" ); document.write( "50=R/2*T \n" ); document.write( "R(T-1)=RT/2 \n" ); document.write( "RT-R=RT/2 \n" ); document.write( "2RT-2R=RT \n" ); document.write( "2RT-RT=2R \n" ); document.write( "RT=2R \n" ); document.write( "T=2R/R \n" ); document.write( "T=2 HOURS FOR THE SLOW TRAIN. \n" ); document.write( "2-1=1 HOUR FOR THE FAST TRAIN. \n" ); document.write( "50=R(2-1) \n" ); document.write( "50=R FOR THE FASTER TRAIN. \n" ); document.write( "PROOF: \n" ); document.write( "50=50(2-1) \n" ); document.write( "50-50 \n" ); document.write( "50=50/2*2 \n" ); document.write( "50=25*2 \n" ); document.write( "50=50 \n" ); document.write( " \n" ); document.write( " |