document.write( "Question 230904: An express and local train leave Grayslake at 3pm and head for chicago 50 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the speed of each train.\r
\n" ); document.write( "\n" ); document.write( "I have this set up I think ok but thats about as far as I get
\n" ); document.write( " rate time distance
\n" ); document.write( "Local x t 50
\n" ); document.write( "Express x(2) t -1 50
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Algebra.Com's Answer #171005 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "50=R(T-1)
\n" ); document.write( "50=R/2*T
\n" ); document.write( "R(T-1)=RT/2
\n" ); document.write( "RT-R=RT/2
\n" ); document.write( "2RT-2R=RT
\n" ); document.write( "2RT-RT=2R
\n" ); document.write( "RT=2R
\n" ); document.write( "T=2R/R
\n" ); document.write( "T=2 HOURS FOR THE SLOW TRAIN.
\n" ); document.write( "2-1=1 HOUR FOR THE FAST TRAIN.
\n" ); document.write( "50=R(2-1)
\n" ); document.write( "50=R FOR THE FASTER TRAIN.
\n" ); document.write( "PROOF:
\n" ); document.write( "50=50(2-1)
\n" ); document.write( "50-50
\n" ); document.write( "50=50/2*2
\n" ); document.write( "50=25*2
\n" ); document.write( "50=50
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