document.write( "Question 230535: Translate the problem into a pair of linear equations in two vaiables. Solve the equations using either elimination or substitution. State your answer for both variables.\r
\n" );
document.write( "\n" );
document.write( "An express train and a local train leave a station at the same time (on separate tracks) and head for a town 50 miles away. The express travels twice as fast as the local and arrives 1 hour ahead of the local. Find the speed of each train. \n" );
document.write( "
Algebra.Com's Answer #170997 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! An express train and a local train leave a station at the same time (on separate tracks) and head for a town 50 miles away. \n" ); document.write( " The express travels twice as fast as the local and arrives 1 hour ahead of the local. \n" ); document.write( " Find the speed of each train. \n" ); document.write( "; \n" ); document.write( "I can't imagine why you would use two variables and two equations on this problem \n" ); document.write( ": \n" ); document.write( "simple time equation would work fine \n" ); document.write( ": \n" ); document.write( "Let s = speed of the slow train \n" ); document.write( "then \n" ); document.write( "2s = speed of the fast train \n" ); document.write( ": \n" ); document.write( "slow train time = fast train time + 1 hr \n" ); document.write( " \n" ); document.write( "Multiply by 2s \n" ); document.write( "2(50) = 50 + 2s \n" ); document.write( "100 - 50 = 2s \n" ); document.write( "2s = 50 \n" ); document.write( "s = 25 mph, slow train and 50 mph fast train \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check solution in time equation \n" ); document.write( " |