document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=230893>Question 230893</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Word Problem One - An old car has to travels a 2-mile route, uphill and down.  Because it is so old, the car can climb the first mile - the ascent - no faster than an average speed of 20 mph.  How fast does the car have to travel the second mile - on the descent it can go faster, of course - in order to achieve an average speed of 30 mph for the trip? (Show a complete algebraic solution for the problem and check the answer.)\r<BR>\n" );
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document.write( "The teacher said set up a table\r<BR>\n" );
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document.write( "Trip		DISTANCE = SPEED x TIME<BR>\n" );
document.write( "UP<BR>\n" );
document.write( "DOWN<BR>\n" );
document.write( "TOTAL\r<BR>\n" );
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document.write( "I am confused as to when to put in x and how to make an equation!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #170995 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=170995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> do an average<BR>\n" );
document.write( "30=(20+x)/2<BR>\n" );
document.write( "60=20+x<BR>\n" );
document.write( "60-20=40 mph<BR>\n" );
document.write( "your teacher might be looking for something diferent,<BR>\n" );
document.write( "but this works </SPAN>\n" );
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