document.write( "Question 230669: the value of a 2 digit number is more than 3 times the sum of its digits. The units digit is 1 more than twice the tens digit. find the 2 digit number. \n" ); document.write( "
Algebra.Com's Answer #170988 by ankor@dixie-net.com(22740)\"\" \"About 
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I had to add some missing information here, hopefully it's correct
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\n" ); document.write( "let 10x + y = the two digit number
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\n" ); document.write( "Write an equation for each statement:
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\n" ); document.write( "\"the value of a 2 digit number is 1 more than 3 times the sum of its digits.\"
\n" ); document.write( "10x + y = 3(x + y) + 1
\n" ); document.write( "10x + y = 3x + 3y + 1
\n" ); document.write( "10x - 3x = 3y - y + 1
\n" ); document.write( "7x = 2y + 1
\n" ); document.write( ":
\n" ); document.write( "\"The units digit is 1 more than twice the tens digit.\"
\n" ); document.write( "y = 2x + 1
\n" ); document.write( ":
\n" ); document.write( " find the 2 digit number.
\n" ); document.write( "Substitute (2x+1) for y
\n" ); document.write( "7x = 2(2x+1) + 1
\n" ); document.write( "7x = 4x + 2 + 1
\n" ); document.write( "7x - 4x = 3
\n" ); document.write( "3x = 3
\n" ); document.write( " x = 1
\n" ); document.write( "then
\n" ); document.write( "y = 2(1) + 1
\n" ); document.write( "y = 3
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\n" ); document.write( "13 is the number
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\n" ); document.write( ":
\n" ); document.write( "See if that's true in the statement:
\n" ); document.write( "\"the value of a 2 digit number is 1 more than 3 times the sum of its digits.\"
\n" ); document.write( "13 = 3(1 + 3) + 1
\n" ); document.write( "13 = 3(4) + 1
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