document.write( "Question 230771: The sum of the digits of a two-digit number is 13. If the digits are reversed, the
\n" ); document.write( "new number is 27 greater than the original number. What is the original two-digit
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Algebra.Com's Answer #170986 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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10x + y = the original two digit number
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\n" ); document.write( "The sum of the digits of a two-digit number is 13.
\n" ); document.write( "x + y = 13
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\n" ); document.write( "If the digits are reversed, the new number is 27 greater than the original number.
\n" ); document.write( "10y + x = 10x + y + 27
\n" ); document.write( "10y - y = 10x - x + 27
\n" ); document.write( "9y = 9x + 27
\n" ); document.write( "Simplify, divide by 9
\n" ); document.write( "y = x + 3
\n" ); document.write( "rearrange to:
\n" ); document.write( "-x + y = 3
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\n" ); document.write( " What is the original two-digit number
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\n" ); document.write( "Use elimination here
\n" ); document.write( "-x + y = 3
\n" ); document.write( "x + y = 13
\n" ); document.write( "----------------addition eliminates x
\n" ); document.write( "2y = 16
\n" ); document.write( "y = 8
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\n" ); document.write( "Find x
\n" ); document.write( "x + 8 = 13
\n" ); document.write( "x = 5
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\n" ); document.write( "58 is the number
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\n" ); document.write( "Check solution in the statement
\n" ); document.write( "If the digits are reversed, the new number is 27 greater than the original number.
\n" ); document.write( "85 = 58 + 27 \n" ); document.write( "

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