document.write( "Question 230867: what is the answer to |3-4x|-3<=8 ? \n" ); document.write( "
Algebra.Com's Answer #170984 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
Equation is |3-4x| - 3 <= 8\r
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\n" ); document.write( "\n" ); document.write( "This means that if the expression within the absolute value sign is positive, then:\r
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\n" ); document.write( "\n" ); document.write( "3-4x - 3 <= 8\r
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\n" ); document.write( "\n" ); document.write( "Combine like terms to get:\r
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\n" ); document.write( "\n" ); document.write( "-4x <= 8\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides by 4 to get:\r
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\n" ); document.write( "\n" ); document.write( "-x <= 2\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides by -1 to get:\r
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\n" ); document.write( "\n" ); document.write( "x >= -2\r
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\n" ); document.write( "\n" ); document.write( "Note that the inequality is reversed when you multiply both sides by -1.\r
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\n" ); document.write( "\n" ); document.write( "If the expression within the absolute value sign is negative, then:\r
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\n" ); document.write( "\n" ); document.write( "-(3-4x) - 3 <= 8\r
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\n" ); document.write( "\n" ); document.write( "This becomes:\r
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\n" ); document.write( "\n" ); document.write( "-3 + 4x - 3 <= 8\r
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\n" ); document.write( "\n" ); document.write( "Combine like terms to get:\r
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\n" ); document.write( "\n" ); document.write( "-6 + 4x <= 8\r
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\n" ); document.write( "\n" ); document.write( "Add 6 to both sides of the equation to get:\r
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\n" ); document.write( "\n" ); document.write( "4x <= 8+6 becomes 4x <= 14\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides of the equation by 4 to get:\r
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\n" ); document.write( "\n" ); document.write( "x <= 14/4\r
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\n" ); document.write( "\n" ); document.write( "You have:\r
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\n" ); document.write( "\n" ); document.write( "x >= -2\r
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\n" ); document.write( "\n" ); document.write( "and:\r
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\n" ); document.write( "\n" ); document.write( "x <= 14/4\r
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\n" ); document.write( "\n" ); document.write( "This is equivalent to -2 <= x <= 14/4\r
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\n" ); document.write( "\n" ); document.write( "We need to confirm these values are accurate.\r
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\n" ); document.write( "\n" ); document.write( "We'll take values inside and outside the limits to see what happens.\r
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\n" ); document.write( "\n" ); document.write( "We'll do:\r
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\n" ); document.write( "\n" ); document.write( "x = -3 (outside limits)
\n" ); document.write( "x = -2 (within limits)
\n" ); document.write( "x = 3 (within limits)
\n" ); document.write( "x = 14/4 (within limits)
\n" ); document.write( "x = 4 (outside limits)\r
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\n" ); document.write( "\n" ); document.write( "When x = -3, |3-4x| - 3 = |3+12| - 3 = |15| - 3 = 15-3 = 12 > 8 so this is NOT ok as it should be.\r
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\n" ); document.write( "\n" ); document.write( "When x = -2, |3-4x| - 3 = |3+8| - 3 = |11| - 3 = 11 - 3 = 8 <= 8 so this IS ok as it should be.\r
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\n" ); document.write( "\n" ); document.write( "When x = 3, |3-4x| - 3 = |3-12| - 3 = |-9| - 3 = 9 - 3 = 6 <= 8 so this IS ok as it should be.\r
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\n" ); document.write( "\n" ); document.write( "When x = 14/4, |3-4x| - 3 = |3 - 14| - 3 = |-11| - 3 = 11 - 3 = 8 <= 8 so this IS ok as it should be.\r
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\n" ); document.write( "\n" ); document.write( "When x = 4, |3-4x| - 3 = |3 - 16| - 3 = |-13| - 3 = 13 - 3 = 10 > 8 so this is NOT ok as it should be.\r
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\n" ); document.write( "\n" ); document.write( "Looks likes these values are good.\r
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