document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=230870>Question 230870</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Two angles of a triangle have the same measure. This measure is equal to one-fourth the measure of the thrid angle. Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #170983 by </B><A HREF=/tutors/aboutme.mpl?userid=likaaka><B>likaaka(51)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=likaaka><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=170983\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> You must remember that the sum of the interior angles of a triangle equals 180 degrees. <BR>\n" );
document.write( "So, if you have two angles that are the same and measure <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+1%2F4+ ALIGN=MIDDLE  ALT=\"+1%2F4+\"   DISABLED_style= \"max-width:90%; height:auto;\" > of the third, begin by naming the third angle x<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x+%2B+2%281%2F4%29x+=+180+ ALIGN=MIDDLE  ALT=\"+x+%2B+2%281%2F4%29x+=+180+\"   DISABLED_style= \"max-width:90%; height:auto;\" > simplify<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+x+%2B+%282%2F4%29x+=+180+ ALIGN=MIDDLE  ALT=\"+x+%2B+%282%2F4%29x+=+180+\"   DISABLED_style= \"max-width:90%; height:auto;\" > find least common denominator to combine like terms<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%284%2F4%29x+%2B+%282%2F4%29x+=+180+ ALIGN=MIDDLE  ALT=\"+%284%2F4%29x+%2B+%282%2F4%29x+=+180+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%286%2F4%29x+=+180+ ALIGN=MIDDLE  ALT=\"+%286%2F4%29x+=+180+\"   DISABLED_style= \"max-width:90%; height:auto;\" > now solve for x by multiplying both sides by <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+4%2F6+ ALIGN=MIDDLE  ALT=\"+4%2F6+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%284%2F6%29%286%2F4%29x+=+%284%2F6%29%28180%29+ ALIGN=MIDDLE  ALT=\"+%284%2F6%29%286%2F4%29x+=+%284%2F6%29%28180%29+\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x = 120 so the third angle measures 120 degrees, now solve for the other 2 angles<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+%281%2F4%29%2A120+ ALIGN=MIDDLE  ALT=\"+%281%2F4%29%2A120+\"   DISABLED_style= \"max-width:90%; height:auto;\" > = 30<BR>\n" );
document.write( "So the other two angles are 30 degrees<BR>\n" );
document.write( "CHECK:<BR>\n" );
document.write( "The sum of the interior angles is 180<BR>\n" );
document.write( "120 + 30 + 30 = 180<BR>\n" );
document.write( "180 = 180 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );