Algebra.Com's Answer #170974 by Alan3354(69443)  You can put this solution on YOUR website! Most classroom problems of this type have integer solutions. \n" );
document.write( "The last term is 24, so try 1, 2, 3, 4, 6 until you find one (it could be + or minus). \n" );
document.write( "2 is a solution, so divide by (x-2). \n" );
document.write( "--> x^3 + 5x^2 + 10x + 12 \n" );
document.write( "-3 is a solution, divide by (3+3) \n" );
document.write( "--> x^2 + 2x + 4 \n" );
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document.write( " Solved by pluggable solver: SOLVE quadratic equation (work shown, graph etc) | \n" );
document.write( "Quadratic equation (in our case ) has the following solutons: \n" );
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document.write( " For these solutions to exist, the discriminant should not be a negative number. \n" );
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document.write( " First, we need to compute the discriminant : . \n" );
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document.write( " The discriminant -12 is less than zero. That means that there are no solutions among real numbers.
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document.write( " If you are a student of advanced school algebra and are aware about imaginary numbers, read on.
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document.write( " In the field of imaginary numbers, the square root of -12 is + or - . \n" );
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document.write( " The solution is , or \n" );
document.write( " Here's your graph: \n" );
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