document.write( "Question 230837: The ancient greeks thought that the most pleasing shape for a rectangle was one for which the ratio of the length to the width was approximately 8 to 5, the golden ratio. if the length of a rectangular painting is 2ft longer than its width, then for what dimensions would the length and width have the golden rule. I was on this path:\r
\n" ); document.write( "\n" ); document.write( "8/5 = x+2/x but that didn't work out.\r
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Algebra.Com's Answer #170963 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
L/W = 8/5 is the golden ratio.\r
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\n" ); document.write( "\n" ); document.write( "The length of a painting is 2 feet more than the width.\r
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\n" ); document.write( "\n" ); document.write( "This makes L = W + 2\r
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\n" ); document.write( "\n" ); document.write( "Golden ratio is L/W = 8/5\r
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\n" ); document.write( "\n" ); document.write( "If L = W + 2, then the golden ratio becomes (W+2)/W = 8/5\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides of this equation by 5 to get:\r
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\n" ); document.write( "\n" ); document.write( "5 * (W + 2)/W = 8\r
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\n" ); document.write( "\n" ); document.write( "Multiply both sides of this equation by W to get:\r
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\n" ); document.write( "\n" ); document.write( "5 * (W + 2) = 8*W\r
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\n" ); document.write( "\n" ); document.write( "Remove parentheses to get:\r
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\n" ); document.write( "\n" ); document.write( "5W + 10 = 8W\r
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\n" ); document.write( "\n" ); document.write( "Subtract 5W from both sides of this equation to get:\r
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\n" ); document.write( "\n" ); document.write( "3W = 10\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides of this equation by 3 to get:\r
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\n" ); document.write( "\n" ); document.write( "W = 10/3\r
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\n" ); document.write( "\n" ); document.write( "If W = 10/3, then L = W + 2 = 10/3 + 2 = 10/3 + 6/3 = 16/3\r
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\n" ); document.write( "\n" ); document.write( "L = 16/3
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\n" ); document.write( "\n" ); document.write( "L/W = (16/3)/(10/3) = (16/3) * (3/10) = 16/10 = 8/5\r
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\n" ); document.write( "\n" ); document.write( "You have the golden ratio when:\r
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\n" ); document.write( "\n" ); document.write( "L = 16/3
\n" ); document.write( "W = 10/3\r
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\n" ); document.write( "\n" ); document.write( "L = W + 2 means L = 10/3 + 2 means L = 10/3 + 6/3 means L = 16/3\r
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\n" ); document.write( "\n" ); document.write( "Both requirements are met.\r
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\n" ); document.write( "\n" ); document.write( "L = W + 2
\n" ); document.write( "L/W = 8/5\r
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